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w^2-14.5w+7=0
a = 1; b = -14.5; c = +7;
Δ = b2-4ac
Δ = -14.52-4·1·7
Δ = 182.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14.5)-\sqrt{182.25}}{2*1}=\frac{14.5-\sqrt{182.25}}{2} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14.5)+\sqrt{182.25}}{2*1}=\frac{14.5+\sqrt{182.25}}{2} $
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